Fun with maths: if cos A + cos B + cos C = 0 = sin A + sin B + sin C
prove that cos 3A + cos 3B + cos 3C = 3 cos( A+ B+ C) proof: we have cos A + cos B + cos C = 0 ...1 sin A + sin B + sin C = 0 ....2 multiply 2nd by i and add (cos A + i sin A ) + ( cos B + i sin B) + (cos C + i sin C) = 0 or e^(iA) + e^(iB) + e^(iC)= 0 as...