驗證網址mathhelpforum.com安全性

secx + tanx = 1/(secx-tanx) - Math Help Forum

You are correct, now just write it as 1/[(1-sinx)/cosx] and proceed further. Alternatively multiply and divide the numerator and denominator by ( secx-tanx) the numerator will reduce ......

網址安全性掃描由 google 提供