Prove that limit (x^2)*[sin(1/x)]=0, x->0? | eNotes
Get an answer for 'Prove that limit (x^2)*[sin(1/x)]=0, x->0?' and find homework help for other Math questions at eNotes ... To prove that lt x-->0 {x^2)[sin(1/x)] = 0. Proof: Method 1: |sin theta| < 1, for any theta. So Lt x--> 0 x^2 {sin(1/x)} should be...